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A projectile with an initial velocity of 48 feet per second is launched from a building 190 feet tall. The path of the projectile is modeled using the equation h(t) = –16t2 + 48…

A projectile with an initial velocity of 48 feet per second is launched from a building 190 feet tall. The path of the projectile is modeled using the equation h(t) = –16t2 + 48…
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A projectile with an initial velocity of 48 feet per second is launched from a building 190 feet tall. The path of the projectile is modeled using the equation h(t) = –16t2 + 48t + 190

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User Michael Gorsuch
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2 Answers

5 votes

Answer:226

Explanation:

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User Anagha
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3 votes

Answer: C.226 feet

Explanation:

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User Claris
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7.6k points
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