Question

Given the reaction at equilibrium:N2(g) + 3H2(g) 2NH3(g) + 91.8kJWhat occurs when the concentration of H2(g) is increased?A)The rate of the forward reaction increases and the concentration of N2(g) decreases.B)The rate of the forward reaction decreases and the concentration of N2(g) increases.C)The rate of the forward reaction and the concentration of N2(g) both increase.D)The rate of the forward reaction and the concentration of N2(g) both decrease.

Answer 1

The forward reaction would increase to start reducing the concentration of N2.

Step-by-step explanation:

Answer 2

A

Step-by-step explanation:

N2(g) + 3H2(g) -> 2NH3(g)

According to Le Chatelier's principle, and since H2(g) is on the left side and a reactant, if it's concentration is increased, the equilibrium shifts to the right and the forward reaction is favoured, leading to the production of more NH3(g). The rate of the forward reaction increases.

As the concentration of H2(g) is increased, the concentration of the other reactant, N2(g) decreases as more of it is used up to react with the excess H2(g)