Question

How do you solve 5y+1=10y^2

Answer 1

`5y+1=10y^2\\10y^2-5y-1=0\\D=(-5)^2-4*10*(-1)=25+40=65=√(65)^2 \\y_1=(5+√(65) )/(20) \\y_2=(5-√(65) )/(20)`

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P.S. Hello from Russia :^)