Question

The decomposition of sulfonyl chloride, SOCl2 is a first order reaction with a half life of 8.75 hours. Calculate the concentration of SOCl2 after 17.0 hours have passed in an experiment where the initial concentration of sulfonyl chloride was .0837M.

Answer 1

`[SOCl_2]=0.0218M`

Step-by-step explanation:

The equations for a first order reaction are:

`(d[A])/(dt)=-k[A]`

`[A]=[A_0]e^(-kt)`

`t(1)/(2)=(\ln 2)/(k)`

1. Calculate the constant of reaction, k:

Use the equation

`t(1)/(2)=(\ln 2)/(k)`

`8.75h=(\ln 2)/(k)`

`k=(\ln 2)/(8.75h)`

`k\approx 0.0792168h^(-1)`

2. Calculate the concentration after 17.0 hours

Use the equation

`[A]=[A_0]e^(-kt)`

`[SOCl_2]=0.0837M\cdot e^{-0.0792168h^(-1)* 17.0h}`

`[SOCl_2]=0.0218M`