Two charged particles are separated by a distance of .99m. If the charge on particle one is .00045C and the charge on particle two is .0000032C. What is the amount of force betw…

Question

asked Dec 5, 2021 160k views

1 Answer

Jithin Sunny · Answer 1 · 2021-12-09T21:34:23+0000

Answer:

The force between the two charges will be 13.22N.

Step-by-step explanation:

The force between the two charges is given by Coulombs law which says

F = k(Q_1Q_2)/(R^2).

In our case

Q_1= 0.00045C ,

Q_2 = 0.0000032C ,

R = 0.99m .

therefore,

F = (9*10^9)((0.00045C)(0.0000032C))/((0.99m)^2).

$\boxed{F=13.22N}$

Hence, the force between the two charges will be 13.22N.