Question

How do i find the area of a trapezoid (pictures provided)

Answer 1

(10x - 5) square units.

Explanation:

Let the lengths of equal sides be x units.

Hence, AB + AD + DC = x + x + x = 3x

Therefore, BC = 3x - 2

`Area \: of \: trapezoid \\ = (1)/(2) (AD + BC) * 5 \\ = (1)/(2) (x + 3x - 2) * 5 \\ = (1)/(2) (4x - 2) * 5 \\ = (1)/(2) * 2 (2x - 1) * 5 \\ = (2x - 1) * 5 \\ = (10x - 5) \: {units}^(2)`