Question

what mass of carbon dioxide gas occupies a volume of 81.3 L at 204kPa and a temperature of 95 degrees celcius

Answer 1

The mass of carbon dioxide will be 238.51g

Step-by-step explanation:

Given:

Volume, V = 81.3 L

Pressure, P = 204 kPa

P = 204000Pa

Temperature, T = 95°C

T = 95 + 273K

T = 368K

mass of CO₂, m = ?

According to the gas law:

PV = nRT

where, R is the gas constant

n is the moles

and the value of R = 8.314 X 10³ L⋅Pa⋅K⁻¹⋅mol⁻¹

n = m/w

where,

m is the mass of the substance

w is the molecular weight

and molecular weight of CO₂ is 44 g

On substituting the value we get:

`204000 X 81.3 = (m)/(44) X 8.314 X 10^3 X 368\\\\m = (204 X 81.3 X 44)/(8.314 X 368) \\\\m = 238.51 g`

Therefore, the mass of carbon dioxide will be 238.51g