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A 50 kg man stands on the surface of a frozen pond. In order to get to the side of the pond he throws his 1 kg shoes at a speed of 10 m/s. After that what’s the speed of the man…

A 50 kg man stands on the surface of a frozen pond. In order to get to the side of the pond he throws his 1 kg shoes at a speed of 10 m/s. After that what’s the speed of the man…
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A 50 kg man stands on the surface of a frozen pond. In order to get to the side of the pond he throws his 1 kg shoes at a speed of 10 m/s. After that what’s the speed of the man? ( neglect all frictions)

asked
User Crou
by
8.4k points

1 Answer

1 vote

Answer:

As per law of conservation of momentum

1 × 10 = 50× v

v = 1/5 m/S

Or

20 cm/s

answered
User Jacek Dziurdzikowski
by
7.6k points
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