Question

Perform the indicated operation.
(w3 +64) ÷ (4 + W)​

Answer 1

Answer is given below with explanations

Explanation:

`\frac{ {w}^(3) + 64}{4 + w} = \frac{ {w}^(3) + {4}^(3) }{4 + w} \\ \: we \: know \: that \: {x}^(3) + {y}^(3) = (x + y)( {x}^(2) - xy + {y}^(2) ) \\ = \frac{(w + 4)( { {w}^(2) - 4w + 16)}^(2) }{w + 4} \\ on \: cancelling \: we \: get \\ the \: answer \: \\ w^(2) - 4w + 16`

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