Question

What is the weight density of a 2.24 in diameter titanium sphere that weights 0.82 lb?

Answer 1

`0.14\ lb/in^(3)`

Step-by-step explanation:

Density is defined as mass ler unit volume, expressed as

`\rho=\frac {m}{v}`

Where m is mass,
`\rho` is density and v is the volume. For a sphere, volume is given as

`v=\frac {4\pi r^(3)}{3}`

Replacing this into the formula of density then

`\rho=\frac {m}{\frac {4\pi r^(3)}{3}}`

Given diameter of 2.24 in then the radius is 1.12 in. Substituting 0.82 lb for m then

`\rho=\frac {0.82}{\frac {4\pi 1.12^(3)}{3}}=0.13932044952427\approx 0.14 lb/in^(3)`