Question

Brian purchases 245 white bouncy balls, 238 yellow bouncy balls, and 84 orange bouncy

balls. He asked his son to divide them up into bags, so that each bag of balls had at least one
of each color in them, and that each bag had the same number of total balls, and that there
were no balls left over. What is the greatest number of balls he can put into each bag?

Answer 1

To find the greatest number of balls that Brian can put into each bag while meeting the given conditions, find the greatest common divisor (GCD) of the three numbers: 245, 238, and 84. The GCD is 7, so the greatest number of balls that Brian can put into each bag is 7.

Step-by-step explanation:

In order to find the greatest number of balls that Brian can put into each bag while meeting the given conditions, we need to find the greatest common divisor (GCD) of the three numbers: 245, 238, and 84.

First, find the GCD of 245 and 238:

Divide 245 by 238 to get a quotient of 1 and a remainder of 7.

Divide 238 by 7 to get a quotient of 34 and a remainder of 0.

Therefore, the GCD of 245 and 238 is 7. Now find the GCD of 7 and 84:

Divide 84 by 7 to get a quotient of 12 and a remainder of 0.

Therefore, the GCD of 7 and 84 is 7. So, the greatest number of balls that Brian can put into each bag is 7.

Answer 2

189 balls divided into 3 bags

Step-by-step explanation: