Question

A sample of neon gas at a pressure of 1.08 atm fills a flask with a volume of 250 mL at a temperature of 24.0 °C. If the gas is transferred to another flask at 37.2 °C and a pressure of 2.25 atm, what is the volume of the new flask?

Answer 1

124.91mL

Step-by-step explanation:

Given parameters:

P₁ = 1.08atm

V₁ = 250mL

T₁ = 24°C

P₂ = 2.25atm

T₂ = 37.2°C

V₂ = ?

Solution:

To solve this problem, we are going to apply the combined gas law;

`(P_(1) V_(1) )/(T_(1) ) = (P_(2) V_(2) )/(T_(2) )`

P, V and T represents pressure, volume and temperature

1 and 2 delineates initial and final states

Convert the temperature to kelvin;

T₁ = 24°C, T₁ = 24 + 273 = 297K

T₂ = 37.2°C , T₂ = 37.2 + 273 = 310.2K

Input the variables and solve for V₂

`(1.08 x 250)/(298) = (2.25 x V_(2) )/(310.2)`

V₂ = 124.91mL