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A cube-shaped satellite has side lengths of 10 centimeters. What is the least amount of aluminum needed to cover the satellite?

At least


square centimeters of aluminum is needed.

asked
User Nam San
by
7.9k points

1 Answer

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Answer:

600 square centimeter.

Explanation:

A cube-shaped satellite has side lengths of 10 centimeters.

So, the total surface area of the satellite is 2(10 × 10 + 10 × 10 + 10 × 10) = 600 sq. cm.

{The total surface area of a cuboid having length L, width W, and height H is given by 2(LW + WH + HL)}

Therefore, the least amount of aluminum needed to cover the satellite will be 600 sq. cm. (Answer)

answered
User Bassel Kh
by
8.5k points

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