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A magician’s stage has a rectangle trapdoor which is (x+ 1/2) by 2x ft. The outside rectangle length is (x+ 16) ft.

Part A. The total area (in square feet) of the stage can be represented by x2 + 27x + 176. Write an expression for the width of the stage.

Part B: Write an expression for the perimeter of the stage.

Part C: The area of the trapdoor is 10 square feet. Find the value of x.

Part D: The magician wishes to have the area of the stage be at least 20 times the area of the trapdoor. Does this stage satisfy his requirement? Explain.

asked
User Sarumont
by
8.0k points

1 Answer

6 votes

Answer:

Part A:-
x +11 ft Part B:-
(4x+54)ft part C:-
x= 2ft

Part D:- Yes it satisfy his requirement

Explanation:

Given that,

length and breadth of Trapdoor are
(x+ (1)/(2) ) by 2x ft.

The Outside length of Rectangle is
(x+16 ) ft.

Part A:- Total area (in square feet) of the stage can be represented by


x^(2) + 27x+ 176. Write an expression for the width of stage.

So, Area of rectangle =
length * breadth


x^(2) + 27x+ 176 = (x+16) * breadth


Breadth = (x^(2) + 27x+ 176)/(x+16)


Breadth = x+11 ft. ................(1)

Part B:- Write an expression for the Perimeter of the stage.

Here, Perimeter of Rectangle =
2(L+B)

=
2(x+16 + x +11)

=
(4x + 54) ft

Part C:- The area of trapdoor is
10 ft^(2). Find the value of x.

So, Area of trapdoor =
10 ft^(2)


(x +(1)/(2)) * 2x =10 ft^(2)


2x^(2) +x - 10 = 0


x = (-1-9)/(4) ,
(-1+9)/(4)


x = (-5)/(2) ,
2

Hence value of x is
2 ft (Neglecting the negative value because

length cannot be negative).

Part D:- The magician wishes to have the area of the stage be at least 20 times the area of the trapdoor. Does this stage satisfy his requirement? Explain.

So, Length of trapdoor is
(2+(1)/(2) ) = (5)/(2) ft

breadth of trapdoor is
2* 2 = 4ft

Now, outside length of Rectangle is =
18ft

And outside breadth of rectangle is =
13ft

Here, Area of trapdoor =
(5)/(2) * 4 = 10ft^(2) ...................(2)

Area of rectangle =
18 * 13= 234 ft^(2) ....................(3)

Thus comparing Equation (1) & (2) we found that

Area of rectangular stage is 20 times greater than the area of trapdoor.

answered
User ZSynopsis
by
8.8k points
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