Question

A gas at 928 kpa, 129 C occupies a volume of 569 L. Calculate the volume at 319 kpa and
32 C.

Answer 1

1255.4L

Step-by-step explanation:

Given parameters:

P₁ = 928kpa

T₁ = 129°C

V₁ = 569L

P₂ = 319kpa

T₂ = 32°C

Unknown:

V₂ = ?

Solution:

The combined gas law application to this problem can help us solve it. It is mathematically expressed as;

`(P_(1) V_(1) )/(T_(1) ) = (P_(2) V_(2) )/(T_(2) )`

P, V and T are pressure, volume and temperature

where 1 and 2 are initial and final states.

Now,

take the units to the appropriate ones;

kpa to atm, °C to K

P₂ = 319kpa in atm gives 3.15atm

P₁ = 928kpa gives 9.16atm

T₂ = 32°C gives 273 + 32 = 305K

T₁ = 129°C gives 129 + 273 = 402K

Input the values in the equation and solve for V₂;

`(9.16 x 569)/(402) = (3.15 x V_(2) )/(305)`

V₂ = 1255.4L