Question

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For what value of the constant K does the equation K x2 + 2x = 1 have two real solutions?

Answer 1

The answer is right

Explanation:

100% sure

Answer 2

Rewrite the given quadratic equation in standard form: Kx 2 + 2x - 1 = 0

Discriminant = 4 - 4(K)(-1) = 4 + 4K

For the equation to have two real solutions, the discriminant has to be positive. Hence we need to solve the inequality 4 + 4K > 0.

The solution set to the above inequality is given by: K > -1 for which the given equation has two real solutions.