asked 43.1k views
4 votes
Mike and Olivia we're comparing their Halloween candy. Mike received 4 times as much candy as Olivia received. Mike then split his candy evenly into 3 piles to eat later. If Olivia received 75 ounces of candy, how many ounces of candy would be in each of mikes piles??

2 Answers

6 votes

Answer:

In each of piles it would be 100 ounces of candy.

Explanation:

Given:

Mike and Olivia we're comparing their Halloween candy.

Olivia received candy = 75 ounces.

Mike received 4 times of candy as Olivia received.

Mike splitted evenly his candy into 3 piles to eat later.

Now, to find the ounces of candy in each of Mike's piles.

Mike received 4 times of olivia received = 75 × 4 = 300.

So, ounces candy Mike received = 300.

Number of piles in which Mike split his candy evenly = 3.

Now, to get the ounces of candy in each of Mike's piles we divide the ounces of candy Mike received by 3:


(300)/(3) \\\\=100\ ounces.

Therefore, in each of piles it would be 100 ounces of candy.

answered
User Bob Goblin
by
7.9k points
5 votes

Answer:

100 ounces of candies.

Explanation:

Given:

Olivia received 75 ounces of candy,

Mike received 4 times as much candy as Olivia received.

Mike then split his candy evenly into 3 piles to eat later.

Question asked:

How many ounces of candy would be in each of mikes piles?

Solution:

Olivia received = 75 ounces of candies

As given that Mike received 4 times as much candy as Olivia received:-

Mike received candies = 4 times of Olivia received

= 4
* 75 = 300 ounces of candies

Now, Mike then split his candy evenly into 3 piles to eat later:-

300
/ 3 = 100 ounces candies

Thus, Mike's have 100 ounces of candies in each pile.

answered
User Nasir
by
8.0k points
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