Question

2.

What is the temperature when the volume is 4L? The original temperature is 200K and the
original volume is 5L.

Answer 1

Yes it is 160K as the first person said

Answer 2

160

Step-by-step explanation:

p*v/t = constant

or

p1*v1/t1 = p2*v2/t2

pressure is not stated in question so we get rid of it on both sides

v1/t1 = v2/t2

we are finding temperature so we flip the entire equation

t1/v1 = t2/v2

200/5 = t2/4

4(200/5) = t2

=160