Question

Ruth began filing an empty water tank at a constant rate of 3 hours the tank has 147 times pi, m^3 liters of water. Approximately what percent of the tank would be full of water after 9 hours.

Answer 1

5.8%

Explanation:

Proportions

If we know the constant rate at which a quantity is changing over time, we can set an equation to model the current quantity as a function of time.

We know Ruth began filling an empty water tank at a constant rate of 3
`m^3` per hour (assuming that unit, not specified in the question).

The tank has a capacity of
`147\pi\ m^3` of water, thus at 9 hours, it has been filled with
`3\cdot 9 = 27 \ m^3` of water.

To compute the percentage of filling, we compare this volume with the total capacity of the tank

`\displaystyle percent=(27)/(147\pi)\cdot 100\%=(27)/(461.8)\cdot 100\%`

`percent=5.8\%`