Question

For the chemical reaction, Li + NaCl <-- --> Na + LiCl, the rate law would be...

A. Rate = k[Li][NaCl]
B. Rate = k[Na] [LiCl]
C. Rate = k[Li] + [NaCl]
D. Rate = k[Na] + [LiCl]

Answer 1

Answer: The rate law for the given chemical equation is
`\text{Rate}=k[Li][NaCl]`

Step-by-step explanation:

Rate law is defined as the expression that expresses the rate of the reaction in terms of the molar concentration of all the reactants each term raised to the power their stoichiometric coefficient in the given balanced chemical equation.

For the given balanced chemical equation:

`Li+NaCl\rightleftharpoons Na+LiCl`

Rate law expression for the reaction:

`\text{Rate}=k[Li][NaCl]`

Order with respect to Li = 1

Order with respect to NaCl = 1

Hence, the rate law for the given chemical equation is
`\text{Rate}=k[Li][NaCl]`