How to solve 2n =(15)/(2) and (1)/(4) =(n)/(5) ???

Question

How to solve
`2n =(15)/(2)` and
`(1)/(4) =(n)/(5)` ???

Answer 1

Explanation:

2n = 15/2

Divide both sides b y 2:

n = 15/2 / 2

= 15/2 * 1/2

= 15/4.

1/4 = n / 5

Multiply both sides by the LCM (20):

20/4 = 20n/5

5 = 4n

n = 5/4.

Answer 2

`2n=(15)/(2)`

Multiply both sides by 2:

`\implies 2 \cdot 2n=2 \cdot (15)/(2)`

`\implies 4n=15`

Divide both sides by 4:

`\implies (4n)/(4)=(15)/(4)`

`\implies n=(15)/(4)`

`\frac14=(n)/(5)`

Multiply both sides by 5:

`\implies 5 \cdot \frac14=5 \cdot (n)/(5)`

`\implies \frac54=n`

`\implies n=\frac54`