Question

Find all zeros and write in factored form
(x-5)(3x^2-8x+6) =0

Answer 1

x = 5, 4/3+i√2/3, 4/3-i√2/3.

Explanation:

(x-5)(3x^2-8x+6) =0

This is in factored form already. 3x^2 - 8x + 6 cannot be factored, it is prime.

One zero is x = 5.

3x^2-8x+6 = 0 Using the quadratic formula:

x = [8 +/- sqrt (64 - 4*3*6]) / 6

x = 4/3 +/- sqrt (-8) / 6

x = 4/3 +/- 2sqrt2 i / 6

x = 4/3 +/- i√2 / 3.