asked 46.0k views
5 votes
How many solutions are there to the equation n^2-13n=-40

asked
User SergioFC
by
7.6k points

2 Answers

0 votes
It has 2 real solutions which are 5 and 8
answered
User Ken Hannel
by
8.5k points
6 votes

Answer:

n = 5

n = 8

Explanation:

n^2 - 13n = -40

Equate everything to zero

n^2 - 13n + 40 = 0

Factorise

(n - 5)(n - 8) = 0

Either

n - 5 = 0

Add 5 to both sides

n - 5 + 5 = 0 + 5

n = 5

Or

n - 8 = 0

Add 8 to both sides

n - 8 + 8 = 0 + 8

n = 8

n = 5 or

n = 8

It has two real solutions

answered
User NickDK
by
7.9k points

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