Question

A 1.78−L sample of hydrogen chloride (HCl) gas at 2.09 atm and 22°C is completely dissolved in 699 mL of water to form hydrochloric acid solution. Calculate the molarity of the solution. Assume no change in volume.

Answer 1

`M=0.960M`

Step-by-step explanation:

Hello,

In this case, it is firstly necessary to compute the dissolved moles of hydrogen chloride into the water as shown below:

`n_(HCl)=(PV)/(RT)=(2.09atm*1.78L)/(0.082(atm*L)/(mol*K)*295.15K)=0.671molHCl`

Thus, the molarity is computed as shown below:

`M=(0.671mol)/(0.699L)=0.960M`

Wherein no change in volume is considered, therefore the volume of the solution was the same volume of water.

Best regards.