In ΔDEF, the measure of ∠F=90°, the measure of ∠E=32°, and FD = 9.6 feet. Find the length of EF to the nearest tenth of a foot.

Question

asked Aug 16, 2021 34.5k views

2 Answers

Braulio · Answer 1 · 2021-08-22T05:49:32+0000

Answer:

$EF=15.4\ ft$

Explanation:

we know that

In the right triangle DEF

tan(E)=(FD)/(EF) ----> by TOA (opposite side divided by adjacent side)

substitute the given values

tan(32^o)=(9.6)/(EF)

solve for EF

$EF=(9.6)/(tan(32^o))=15.4\ ft$