Question

If the general solution of a differential equation is ​y(t)equals=Upper C e Superscript negative 4 t Baseline plus 7Ce−4t+7​, what is the solution that satisfies the initial condition ​y(0)equals=1010​?

Answer 1

a

Explanation:

Answer 2

`y(t) = 3e^(-4t)+7`

Explanation:

`y(t) = Ce^(-4t)+7`

At y(0) = 10, when t = 0, y = 10.

`y(0) = 10 = Ce^(-4*0)+7`

`10 = C+7`

`C = 3`

Hence, the solution is

`y(t) = 3e^(-4t)+7`