Question

X=A- B/A. How to find A?

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Answer 1

A =
`( x+√(x^2+4b))/(2), ( x-√(x^2+4b))/(2)`

Explanation:

First manipulate the equation as such,

`x=A-(B)/(A)`

`0=A - (B)/(A) - X`

`0=A^2 -AX - B`

Then use the quadratic formula,

`x= (-b\pm√(b^2-4ac) )/(2a)` when,
`0 = ax^2 +bx +c`.

Which gives
`A= ( x+√(x^2+4b))/(2), ( x-√(x^2+4b))/(2)`.