Question

If n and pare positive integers and 4n/P = V1024, then

the product of n and p is:
(A) -1
(B) 20
(C) 24
(D) 28
(E) 32

Answer 1

Product of n and p is 32 out of available options ! correct option is (E) 32

Explanation:

Here we have , n and pare positive integers and 4n/P = V1024, then we need to find the product of n and p . Let's find out:

According to question we have following equation

⇒
`(4n)/(p) = √(1024)`

⇒
`(4n)/(p) = \sqrt{32(32)`

⇒
`(4n)/(p) = \sqrt{32^2`

⇒
`(4n)/(p) = 32`

⇒
`n=8p`

Now , product of n and p is :

⇒
`np`

⇒
`(8p)p`

⇒
`8p^2`

Value of p is positive integer So , Let f(p)=
`8p^2` :

`f(1)=8(1)^2=8\\f(2)=8(2)^2=32\\f(3)=8(2)^3=64`

Hence , Product of n and p is 32 out of available options ! correct option is (E) 32 .