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A 5.00-kg block of ice is sliding across a frozen pond at 2.00 m/s. A 7.60-N force is applied in the direction of motion. After the ice block slides 15.0 m, the force is removed. The work done by the applied force isA 5.00-kg block of ice is sliding across a frozen pond at 2.00 m/s. A 7.60-N force is applied in the direction of motion. After the ice block slides 15.0 m, the force is removed. The work done by the applied force is

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User Vigbyor
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1 Answer

5 votes

Answer:

Step-by-step explanation:

work done by applied force

= force x displacement

= 7.6 x 15 m

= 114 J .

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User Callie
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