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The kinetic energy K (in joules) of a falling apple is represented by K=v22, where v is the speed of the apple (in meters per second). How fast is the apple traveling when the kinetic energy is 32 joules? The apple is traveling at meters per second.

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User Jiehfeng
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1 Answer

3 votes

Answer: 1.455 m/s

Step-by-step explanation: k = 22v defines the motion of falling apple.

With k as kinetic energy and v as velocity.

We are to find the value of v at k = 32 joules

32 = 22v

v = 32/ 22

v = 1.455 m/s

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User Artanis Zeratul
by
7.3k points

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