Question

What is the value of the discriminant of the quadratic equation -2^3=-8x+8

Answer 1

the value of the discriminant of the quadratic equation
`-2x^2=-8x+8` is
`D =0` .

Explanation:

Here we need to find What is the value of the discriminant of the quadratic equation -2x^2=-8x+8 or ,
`-2x^2=-8x+8` .

We know that for a quadratic equation ,
`f(x) = ax^2+bx+c` , Discriminant is :

⇒
`D = b^2-4ac`

Now , let's frame equation
`-2x^2=-8x+8` in form of
`f(x) = ax^2+bx+c` :

⇒
`-2x^2=-8x+8`

⇒
`2x^2-8x+8=0`

⇒
`x^2-4x+4=0`

Comparing values we get that here , a=1 , b = -4 , c = 4 . Putting these values in
`D = b^2-4ac` :

⇒
`D = (-4)^2-4(1)(4)`

⇒
`D =16-16`

⇒
`D =0`

Therefore , the value of the discriminant of the quadratic equation
`-2x^2=-8x+8` is
`D =0` .