Question

Calculate the mass of Cu(NO3)2.4H2O required to prepare 100.0 mL of 0.200 M solution.

Answer 1

8921.96g

Step-by-step explanation:

Molar mass of Cu (NO3)2.4H2O= 446.0982g/mol

Number of mole = concentrate × volume

n= 100×0.2=20

No of mole= mass/molar mass

Mass= 20×446.0982

Mass= 8921.96g

Mass = 8.9kg.