Question

Solve the system of equations 3x + y = 3 and 7x + 2y = 1.

Answer 1

Explanation:

3x+y = 3.........equation 1

7x+2y = 1.........equation 2

Multiplying equation 1 by 2 and Solving both

6x+2y = 6

7x+2y =1

- - -

-x = 5

Therefore x = -5

Putting x= -5 in equation 1

3 * -5 +y = 3

-15 + y = 3

y = 3+15

therefore y = 18

Hope it helped

Answer 2

`x=-5\\y=18`

Explanation:

Given equations:

`3x + y = 3` Equation:1

`7x + 2y = 1` Equation:2

Multiplying Equation:1 by '2'

`6x+2y=6` Equation:3

Using elimination method:

Subtract Equation:3 from Equation:2:

`7x+2y-(6x+2y)=1-6\\\\7x+2y-6x-2y=-5`

Solving the like terms:

`7x-6x=-5\\\\x=-5`

Putting the value of 'x' in Equation:1

`3x + y = 3`

`3(-5) + y = 3\\\\-15+y=3\\\\`

Adding '15' both sides:

`y=3+15\\\\y=18`

The solution of the equations is:

`x=-5\\y=18`