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You have a culture of yeast that is at a concentration of 6.74 x 10^6 cells/ml. You dilute the sample 1:100, and then 1:100 again, and finally you dilute the sample an additional 1:3. You add 0.1 ml of the final dilution to a spread plate.

1. Assuming that most of the cells in the original culture were living, how many CFUs do you expect to count on your spread plate the next day?

1 Answer

5 votes

Answer:

22 cells

Step-by-step explanation:

The concentration of numbers of cells = 6.74 x 10⁶ cells/ml

Dilution stages includes = 1:100 ; 1:100 & 1:3

The consecutive dilution stages can be calculated as:

= (6.74 x 10⁶) × (1/100)(1/100)(1/3)

= 222.42 cells/ml

= 2.22 × 10² cells/ml

So after addition 0.1 ml of the final dilution to a spread plate, the number of CFUs ( Colony forming units) we expect to count will be:

= (2.22 × 10² cells/ml)(0.1 ml)

= 22.2 cells

≅ 22 cells.

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User Ryan Loggerythm
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