Question

In a titration of 50 ML of 0.20m NaOH is used to neutralize 10.0 ML of HCL. Calculate the molarity of the acid

Answer 1

1M

Step-by-step explanation:

First, let us write a balanced equation for the reaction. This is illustrated below:

NaOH + HCl —> NaCl + H2O

From the equation above,

nA (mole of acid) = 1

nB (mole of the base) = 1

Data obtained from the question include:

Vb (volume of base) = 50mL

Mb (Molarity of base) = 0.2M

Va (volume of acid) = 10mL

Ma (Molarity of acid) =?

Using MaVa/MbVb = nA/nB, we can calculate the molarity of the acid as follow:

Ma x 10/0.2 x 50 = 1

Cross multiply to express in linear form

Ma x 10 = 0.2 x 50

Divide both side by 10

Ma = (0.2 x 50)/10

Ma = 1M

The molarity of the acid is 1M