asked 125k views
1 vote
At a carnival, you can try to ring a bell by striking a target with a 11.7-kg hammer. In response, a 0.378-kg metal piece is sent upward toward the bell, which is 5.13 m above. Suppose that 18.0 percent of the hammer's kinetic energy is used to do the work of sending the metal piece upward. How fast must the hammer be moving when it strikes the target so that the bell just barely rings

asked
User TWGerard
by
7.9k points

2 Answers

3 votes

Answer:

Step-by-step explanation:

mass of hammer, Mh = 11.7 kg

mass of metal, Mm = 0.378 kg

height, h = 5.13 m

According to the transformation of energy

Potential energy of metal piece = 18% of kinetic energy of hammer

Mm x g x h = 18 % of 0.5 x Mh x v²

where, v is the velocity of hammer

0.378 x 9.8 x 5.3 = 0.18 x 0.5 x 11.7 x v²

v² = 18.65

v = 4.31 m/s

Thus, the velocity of hammer is 4.31 m/s.

answered
User Roman Khimov
by
8.4k points
3 votes

Answer:

4.25035202162 m/s

Step-by-step explanation:


m_h = Mass of hammer = 11.7 kg


m_m = Mass of metal piece = 0.378 kg

g = Acceleration due to gravity =
9.81\ m/s^2

h = Height = 5.13 m

Energy required to raise the bell


U=m_mgh\\\Rightarrow U=0.378* 9.81* 5.13\\\Rightarrow U=19.0229634\ J

From the question we have


19.0229634=0.18* (1)/(2)m_h* v^2\\\Rightarrow v=\sqrt{(19.0229634* 2)/(0.18* 11.7)}\\\Rightarrow v=4.25035202162\ m/s

The speed of the metal piece is 4.25035202162 m/s

answered
User Bob Ensink
by
7.4k points
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