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4 votes
Josie's GPS shows that she traveled 20 miles in her car. Her car's odometer is slightly off and measures the distance as 24 miles. Josie's GPS shows that she traveled 20 miles in her car. Her car's odometer is slightly off and measures the distance as 24 miles.

asked
User Ovidio
by
8.5k points

1 Answer

6 votes

Answer:

20%.

Explanation:

We have been given that Josie's GPS shows that she traveled 20 miles in her car. Her car's odometer is slightly off and measures the distance as 24 miles. We are supposed to find the percent error for the given scenario.


\text{Percent error}=\frac{|\text{Exact}-\text{Approximation}|}{\text{Exact}}* 100\%


\text{Percent error}=(|20-24|)/(20)* 100\%


\text{Percent error}=(|-4|)/(20)* 100\%


\text{Percent error}=(4)/(20)* 100\%


\text{Percent error}=(4)/(1)* 5\%


\text{Percent error}=20\%

Therefore, error percent in distance is 20%.

answered
User Mark Mcmurray
by
8.4k points
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