Question

How do you find the vertex of the equation y=(x-3)^2+2?

Answer 1

Explanation:

put x-3=0

x=3

when x=3,y=2

so vertex is (3,2)

Answer 2

this is my explanation

Explanation:

Graph the parabola using the direction, vertex, focus, and axis of symmetry.

Direction: Opens Up

Vertex:

(

3

,

2

)

Focus:

(

3

,

9

4

)

Axis of Symmetry:

x

=

3

Directrix:

y

=

7

4

x

y

1

6

2

3

3

2

4

3

5

6

...