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The product of addition of bromine to (R)-3-buten-2-ol will bea. a 50:50 mixture of enantiomers.b. a mixture of enantiomers formed in unequal amounts.c. a 50:50 mixture of diastereomers.d. a mixture of diastereomers formed in unequal amounts.e. optically inactive.

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User HimanAB
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2 votes

Answer:

Option D is the answer

D. a mixture of diastereomers formed in unequal amounts.

Step-by-step explanation:

Chiral intermediates give chiral products

- form unequal mixtures of diastereomers

- transition states are now diastereotopic

• Optically active reactants leads to optically active products.

find attached a diagram of the reaction.

The product of addition of bromine to (R)-3-buten-2-ol will bea. a 50:50 mixture of-example-1
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User Pieter Ennes
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