Question

Determine the equation of a circle with its centre at the origin in the Cartesian plane and with a radius of 2√3 units​

Answer 1

x^2 + y^2 = 12

Explanation:

For a circle with the center at the origin [(h,k) is (0,0)]

use the formula:

x^2 + y^2 = r^2

In this case r is 2sqroot3.

(2sqroot3)^2 is 12.

2•2•sqrt3•sqrt3

= 4•3

= 12

So we get,

x^2 + y^2 = 12