Question

Suppose there are 50,000 deer in a forest

and the growth factor for the population is 1.2
per year. Write an equation you could use to
find the deer population p in n years.

Answer 1

deer population p in n years is
`p=50,000(1.2)^n` .

Explanation:

Here we have , Suppose there are 50,000 deer in a forest and the growth factor for the population is 1.2 per year. We need to Write an equation you could use to find the deer population p in n years. Let's find out:

We have , initially 50,000 deer in a forest . Every year population of deer increases by a factor of 1.2 , i.e. it increases exponentially depending on number of years .

For 1 year the population is increased by

⇒
`50,000(1.2)`

For 2 year the population is increased by

⇒
`50,000(1.2)^2`

So , For n year the population is increased by

⇒
`50,000(1.2)^n`

Therefore , deer population p in n years is
`p=50,000(1.2)^n` .