Question

like K has a slope of -5. like J is perpendicular to link K and passes through the point {5,9}. create the equation for like J

Answer 1

y = (1/5)x + 8

Explanation:

Perpendicular lines have slopes that are negative reciprocals of each other, so the slope of line J is ...

-1/(-5) = 1/5

We can use this with the given point in the point-slope form of the equation of a line:

y = m(x -h) +k . . . . . . . line with slope m through point (h, k)

y = (1/5)(x -5) +9

y = 1/5x +8 . . . . . simplified