Question

Evaluate 5c+cd5c+cd5, c, plus, c, d when c=\dfrac15c=

5
1
​
c, equals, start fraction, 1, divided by, 5, end fraction and d=15d=15d, equals, 15.

Answer 1

4

Explanation:

The function is given as 5c+cd, c=1/5 and d=15d.

We evaluate by substituting the given values of c and d in the function:

`5c+cd, c=1/5 \ \ \, d=15\\\\=5* (1)/(5)+(1)/(5)* 15`

`=1++3\\\\=4`

After substituting, we find the function's equivalent as 4.

Hence, the value of the function is 4