asked 228k views
2 votes
The bottle of Wang resin you have been provided with indicates the quantity of surface linker to be 0.75 mmol/g. The bottle contains 675mg resin, and you use the remainder in your synthesis. How many mmol linkers are present on this mass of resin

asked
User Jan Petr
by
8.2k points

1 Answer

1 vote

Answer:


n_(linerks)=0.506mmol

Step-by-step explanation:

In this case, a mole-mass relationship is enough to compute the amount in mmol of the linkers that are present on such mass of resin as shown below:


n_(linerks)=675mg*(1g)/(1000mg)*(0.75mmol)/(1g) \\n_(linerks)=0.506mmol

Best regards.

answered
User Uelordi
by
8.6k points
Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.