Question

A circular saw blade with a radius of 0.145 m starts from rest and turns in a vertical plane with a constant angular acceleration of 2.00 rev/s2. After the blade has turned through 155 revs, a small piece of the blade breaks loose from the top of the blade. After the piece breaks loose, it travels with a velocity that is initially horizontal and equal to the tangential velocity of the rim of the blade. The piece travels a vertical distance of 0.820 m to the floor.

How far does the piece travel horizontally, from where it broke off the blade until it strikes the floor?

Answer 1

Horizontal distance travelled will be x= 9.40 m

Step-by-step explanation:

Detailed solution is attached