Question

Suppose that 0.25 mole of gas C was added to

the mixture without changing the total pressure of
the mixture.
What is the partial pressure of C?​

Answer 1

Pi = 0.25[P(TTL)/n(TTL)]

Step-by-step explanation:

Let Total Pressure = P(TTL) and Total moles =n(TTL) => n(i)/n(TTL) = P(i)/P(TTL)

Given n(i) = 0.25 => Pi = 0.25[P(TTL)/n(TTL)]

Answer 2

0.12 atm C

Step-by-step explanation:

Edg 2020/21