Question

How do i find the first term of a geometric sequence when i know a3= 1/8 and a6= 1 ?

Answer 1

Explanation:

nth term = ar^(n-1)

a3 = 1/8; ar² = 1/8

a6 = 1; ar⁵ = 1

`ar^(2)*r^(3)=1\\\\(1)/(8)*r^(3)=1\\\\r^(3)=1*8\\\\r^(3)=8\\\\r^(3)=2^(3)\\\\r=2`

`ar^(2)=(1)/(8)\\\\a*2^(2)=(1)/(8)\\\\a*4=(1)/(8)\\\\a=(1)/(8*4)\\\\a=(1)/(32)\\\\`