Answer:
p(t) = 0.19e0.10t 
=>p'(t) = 0.19e0.10t (0.10*1) 
=>p'(t) = 0.019e0.10t 
 
t = 0 represents 1994 
for 2002, t=2002-1994 =8 
 
in 2002 
average price =p(8) 
=>average price = 0.19e0.10*8 
=>average price =0.422853... million 
 
rate of increase =p'(8) 
=>rate of increase = 0.019e0.10*8 
=>rate of increase =0.0422853... million per year 
 
p(8)=$ 0.42 million 
p'(8)=$ 0.042 million per year