Question

A flask has a mass of 78.23 g when empty and 593.63 g when filled with water. When the same flask is filled with concentrated sulfuric acid, H2SO4, its mass is 1026.57 g. What is the density of concentrated sulfuric acid

Answer 1

1840.01 kg/m³

Step-by-step explanation:

From Archimedes's principle.

mass of H₂SO₄/ mass of water = Density of H₂SO₄/Density of water.

M/M' = D/D'................ Equation 1

Where M = mass of H₂SO₄, M' = mass of water, D = Density of H₂SO₄, D' = Density of water.

make D the subject of the equation

D = D'(M/M').................. Equation 2

Given: M' = 593.63-78.23 = 515.4 g = 0.5154 kg, M = 1026.57-78.23 = 948.34 g = 0.94834 kg, D' = 1000 kg/m₃

Substitute into equation 2

D = 1000(0.94834/0.5154)

D = 1840.01 kg/m³

Hence the density of concentrated sulfuric acid = 1840.01 kg/m³

Answer 2

1.84 g/mL

Step-by-step explanation:

If we want to calculate the density we have to keep in mind that we need the mass and the volume of the Sulfuric acid
`H_2SO_4`.

`D=(Mass)/(Volume)`

To calculate the mass we have to substract the mass of the flask from the mass of the flask plus
`H_2SO_4`, so:

`Mass~of~H_2SO_4=1026.57~g-78.23~g=948.34~g~H_2SO_4`

To calculate the volume we have to use the water information. The first step is the calculation of the mass of water:

`Mass~of~H_2O~=~593.63~g-~78.23~g=~515.4~g~H_2O`

The density of water is 1 g/mL, so we can use this value to calculate the volume of the flask:

`515.4~g~H_2O(1~mL)/(1~g)=~515.4~mL~H_2O`

Therfore the volume of the flask is 515.4 mL

Finally, we have to divide the mass by the volume:

`D=(948.34~g)/(515.4~mL)=1.84~g/mL`

The density of
`H_2SO_4` is 1.84 g/mL