Question

The cup was filled at a constant rate. It started empty. After 2 seconds, it held 70 cm cubed of water.Find the percent of the cup that is filled with water after 3 seconds.

Answer 1

In 3 seconds the cup is filled with
`105\ cm^3`.

Explanation:

Given:

2 seconds =
`70\ cm^3` water

We need to find the percent of the cup that is filled with water after 3 seconds.

Solution:

Now Given:

The cup was filled at a constant rate.

First we will find the volume of water filled in the cup after 1 seconds.

2 seconds =
`70\ cm^3` water

1 seconds = Volume of water filled in 1 second.

By Using Unitary method we get;

Volume of water filled in 1 second =
`(70)/(2)= 35\ cm^3`

Now we will find the volume of water filled in the cup after 3 seconds.

1 second =
`35\ cm^3` of water is filled

3 seconds = volume of water filled in the cup after 3 seconds

Again by using Unitary method we get;

volume of water filled in the cup after 3 seconds =
`35 * 3 = 105\ cm^3`

Hence In 3 seconds the cup is filled with
`105\ cm^3`.

To find the percent of the cup filled with water after 3 seconds we would required the dimensions of the cup which is not available in the question.